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Colin the Mathmo

I don't know what 55² is, and I wouldn't bother to compute it by hand.

But I do know:

a²-b² = (a-b)(a+b)

a² = (a-b)(a+b)+b²

Setting a=55 and b=5 we get

55² = (55-5)(55+5) + 5²

Suddenly it's obvious, not because of the numbers, but because of the structure.

The facility with numbers is an epiphenomenon.

2/n, n=2

@ColinTheMathmo - if you haven't read it yet, you might enjoy the section in 𝑆𝑢𝑟𝑒𝑙𝑦 𝑌𝑜𝑢 𝑀𝑢𝑠𝑡 𝐵𝑒 𝐽𝑜𝑘𝑖𝑛𝑔, 𝑀𝑟. 𝐹𝑒𝑦𝑛𝑚𝑎𝑛 about Feynman's calculational methods - and how Hans Bethe was better.

@johncarlosbaez Thanks for the memory!

Yes, I know "Surely You're Joking, Mr. Feynman" *very* well, and I'm familiar both with his techniques, and the claim that Bethe was better.

Great reference.

@ColinTheMathmo
I didn't know about that formula, where does b comes from?
If I want to calculate another squared number how do I get b?

@Andres So the starting point is the "Difference of Two Squares" formula. So we have:

a²-b² = (a-b)(a+b)

You can go ahead and check that to make sure it's valid.

Then we can switch is around to get:

a² = (a-b)(a+b) + b²

Now when we want to square a number (call it "a") we have a free choice of "b" to see if we can make it easy.

Take 62² for example. Then choosing b=2 gives us:

62² = (62-2)(62+2) + 2²

That's (60 times 64) plus 4.

Now, 60 times 64 is 60 times 60 (which is 3600) plus 4 times 60 (which is 240) so we get:

62² = (60 times 64) plus 4

62² = (3600 + 240) + 4

62² = 3844 ... and we're done.

But ...

1/n

@ColinTheMathmo I remember learing that (n5)^2 = n(n+1)25 (sorry for the atrocious notation mixing multiplication with concatenation), when I was very young, as a 'magic formula'. One of those things that just lived in my head without further thought - until now!

@ColinTheMathmo

For the square of a number ending on 5, there is another (and quicker) rule: it always ends on 25 and you need to put n * (n+1) in front. Hence 55 squared: 5 times 6 equals 30 and write 25 next to it; so 3025. So 75 squared would be 7 times 8 followed by 25, or 5625. The proof is very straightforward, but I’ll leave it to the reader 😎

@ColinTheMathmo if you like these mental calculations, I highly recommend “Dead Reckoning - Calculating without Instruments” by Ronald W. Doerfler.

@ColinTheMathmo I once shared this simple trick to a friend who is a professor at a university college. He told me a few days later that he used this trick during a lecture for chemistry students while calculating the results of an experiment on the blackboard. It seems they were very impressed that the could come up with the result (squaring a number ending in 5) in a split second, without the use of a calculator! It’s just a matter of seeing/knowing some simple patterns and a bit of practice.

@wernerkuper I know it well. I've not used it for a while so it would probably take a few minutes to find my copy.

@wernerkuper Indeed, and if you look elsewhere in this thread you will find that I have explained the proof.

I teach these sorts of things, and how they work, and much more besides, in math masterclasses.

@ColinTheMathmo
My grandmother gave me this trick:
When you need to calculate the square of a number ending in 5 (a5), you write down "25" and put (a+1)a in front of it.

In your example: 25 with 30 in front: 3025.

Later, I updated the trick for a5 × b5 =
(The average of (a+1)b and (b+1)a) × 100 + 25.

It works, but it's still a trick...

@cvwillegen Yup, and all explained in other branches of this thread. At all comes back to the difference of two squares formula.

It's a lovely little thing.