Charlotte Kirchhoff-Lukat<p><span class="h-card" translate="no"><a href="https://mathstodon.xyz/@MotivicKyle" class="u-url mention">@<span>MotivicKyle</span></a></span> The history of the <a href="https://mathstodon.xyz/tags/symplectic" class="mention hashtag" rel="tag">#<span>symplectic</span></a> <a href="https://mathstodon.xyz/tags/category" class="mention hashtag" rel="tag">#<span>category</span></a> in this form, the Wehrheim-Woodward category, is roughly as follows:<br />People wanted to construct a symplectic category with more general morphisms than symplectomorphisms (which only exist between diffeomorphic manifolds). The idea of using Lagrangian correspondences is due to Weinstein and his observation that symplectomorphisms are examples. (Weinstein's philosophy: "Everything is a Lagrangian.")<br />This, of course, does not work due to smooth Lagrangian correspondences not always composing smoothly. <br />The Wehrheim-Woodward construction avoids this transversality issue entirely by taking as morphisms paths of relations modulo composing individual relations in the sequence that can be smoothly composed -- as far as I am aware, nobody has found a way of making a nice category with only smoothly composable relations. <br />But now this note by Weinstein shows that, actually, every morphism in the WW category has a representative path consisting of *at most* two non-composable Lagrangian relations, resulting in the span picture. I was somehow surprised by that!</p>