Dani @DaniPhii@mathstodon.xyz

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Hi @christianp! Would you like to have a look at this? https://keybase.io/blog/keybase-proofs-for-mastodon-and-everyone

Well, this is nice. 👀

Current status: testing TLSv1.3 and setting some HTTP headers.

My previous toot is intended to verify my identity with Keybase. So I must thank @ryanmaynard for this post. https://ryanmaynard.co/mastodon-keybase

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Hi everybody! I'm back over here! 🙂

Some days ago I had LineageOS for microG installed on my BQ Aquaris M5 and I gotta say I'm glad I did so. https://lineage.microg.org/

Interesting…
\[\begin{align}\sqrt[3]{50+\sqrt{2527}}&+\sqrt[3]{50-\sqrt{2527}}=4\\
\sqrt[3]{85+\sqrt{7252}}&+\sqrt[3]{85-\sqrt{7252}}=5\\
\sqrt[3]{44+\sqrt{1944}}&+\sqrt[3]{44-\sqrt{1944}}=4\\
\sqrt[3]{1414+\sqrt{1999404}}&+\sqrt[3]{1414-\sqrt{1999404}}=14\\
\sqrt[3]{3515+\sqrt{12355252}}&+\sqrt[3]{3515-\sqrt{12355252}}=19\\
\sqrt[3]{171710+\sqrt{29484324108}}&+\sqrt[3]{171710-\sqrt{29484324108}}=70\\
\sqrt[3]{3015103+\sqrt{9090846100636}}&+\sqrt[3]{3015103-\sqrt{9090846100636}}=182\end{align}\]

I'm looking for identities like this one that I've already found:
\[\sqrt[3]{4n^3+6n+\sqrt{16n^6+48n^4+36n^2+8}}+\sqrt[3]{4n^3+6n-\sqrt{16n^6+48n^4+36n^2+8}}=2n\]

Waiting for my Vega Minx by Raphaël Mouflin! https://mathstodon.xyz/media/imbrocB4ZzP1GXGAeLg

I'm sooo tired. I'm teaching more maths tomorrow. Good night.

Next week I'm paying for one of these, I can't believe it yet. https://www.youtube.com/watch?v=lgoFNDcRooE

I really love Undertale. What a game.

Now I've got a Rubik's \(1^3\) too! I've made it myself. 🙂 https://mathstodon.xyz/media/6uE7h5z4N6yHqFm5vsc

I've got \(2^3\), \(3^3\), \(4^3\), \(5^3\), \(6^3\) and \(7^3\) Rubik's cubes. I wanna get the next one. https://www.amazon.co.uk/dp/B01N5ECDEU

I got those formulae knowing that \((a+b)^2\) \(+\) \((a-b)^2\) \(=\) \(\sum_{k=0}^{\frac{n - (n \bmod 2)}{2}}\) \(2\) \({n \choose 2k}\) \(a^{n-2k}\) \(b^{2k}\).

\[{P_{n}}^6 = \frac{5 \cdot (-1)^{n + 1}}{128} + \sum_{k=0}^{\frac{n - (n \bmod 2)}{2}} {n \choose 2k} \cdot \Bigg(\frac{99^n \cdot 9800^k}{256 \cdot 9801^k} - \frac{3 \cdot (-17)^n \cdot 288^k}{128 \cdot 289^k} + \frac{3^{n+1} \cdot 5 \cdot 8^k}{256 \cdot 9^k}\Bigg) \]