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@ColinTheMathmo I've think I'm using \param instead of \epsilon (and set the value of \param in the preamble) because I've already swapped notation: it's typical to use \(\gamma\) for the parameter in question, but I noticed after draft 1 I was already using \(\gamma\) for something else. Let's hope I remembered this and used \param everywhere...

Aaarg, I'm using \(\epsilon\) and \(\varepsilon\) (for two different values) in the same equation. I fear it may be time to burn this laptop and start my PhD again from scratch.

:chalkdust_scorpion: Do you love maths magazines and the first number that is neither prime nor semiprime? Then you'll love our 8th issue! chalkdustmagazine.com/

:chalkdust_scorpion: Do you love maths magazines and vertices of cubes? Then you'll love our 8th issue! chalkdustmagazine.com/

This has to be the weirdest setting for a sci-fi novel. This plot synopsis is so bizarre!

en.wikipedia.org/wiki/The_Last

\[\sqrt{\sqrt{9} - \sqrt{8}} = \sqrt{2} - \sqrt{1}\]

Issue 08 of @chalkdustmag is finished and has been sent to the printers. :chalkdust_scorpion: :chalkdust_scorpion: :chalkdust_scorpion:

@bmreiniger @chalkdustmag Hmm, that looks like it might be an improvement. I'll check the code I used to find the shortest route and get back to you...

Mathematical fact made entirely of straight lines (based on @Pecnut's idea):
\(\left|\frac{\mathsf{\Xi}}{|\mathsf{\Xi}|}\right|=1\)

The early-bird discount for the MathsJam Annual Gathering closes in two hours. Register here, payment details in the link you get sent:

solipsys.co.uk/MathsJamRegiste

More information here:

solipsys.co.uk/cgi-bin/MJ_Wiki

... or maybe this is worse:

\(x+\mathrm{x}=\mathsf{x}\)
\(\mathsf{x}+\mathrm{x}=4x\)
\(\mathsf{x}+x=3\mathrm{x}+1\)
Find \(x\), \(\mathrm{x}\), and \(\mathsf{x}\).

@mscroggs Yep that's why I was wandering if you considered these x's different variables or not. If you are, that actually defines a plane in 3 dimensions!

The absolute worst way to write a simultaneous equations question:

\({\color{yellow}x} + {\color{blue}x} = {\color{green}x}\)
\({\color{green}x} + {\color{blue}x} = 4{\color{yellow}x}\)
\({\color{yellow}x} + {\color{green}x} = 3{\color{blue}x}+1\)
Find \(\color{yellow}x\), \(\color{blue}x\), and \(\color{green}x\).

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