@kimreece They don't throw a heavy burden on me. I'm chewing on a granite slab.

We've emailed all Librem 5 backers with the batch they are most likely to be in puri.sm/posts/what-librem-5-ba #Purism #Librem5

21st Century M101

Image Credit: NASA, ESA, CXC, JPL - Caltech, STScI

Messier 45: The Daughters of Atlas and Pleione

@ColinTheMathmo Hi, I didn’t write in more detail, so here you can have anything. The math problems of the millennium or the increase in the number of Wilstrass that happened this morning on the IBM computers. my friend I will be more detailed.

@ColinTheMathmo Are there any other mathematical problems solved this morning?

SOLUTION TO 315. THE HAT-PEG PUZZLE. (1/2)

The moves will be made quite clear by a reference to the diagrams, which show the position on the board after each of the four moves. The darts indicate the successive removals that have been made. It will be seen that at every stage all the squares are either attacked or occupied, and that after the fourth move no queen attacks any other. In the case of the last move the queen in the top row might also have been moved one

@ejk
1. Euler number(constant) $e=2.7182818284590452353602874713527$ What sign did you specify this number? You can try to calculate for this series:
$e = \sum\limits_{n = 0}^{\infty} \frac{1}{n!} = \frac{1}{1} + \frac{1}{1} + \frac{1}{1\cdot 2} + \frac{1}{1\cdot 2\cdot 3} + \cdots$ I found more Mentions here: mathsisfun.com/numbers/e-euler
$\frac{n!}{k!(n-k)!} = \binom{n}{k}$
$f(n) = n^5 + 4n^2 + 2 |_{n=17}$ 