Given \(M, N\), matrices, let

\[m_{ij} = \lfloor \log_2 M_{ij} \rfloor \]

and similarly for \(n\). Then \(M_{ij} \approx 2^{m_{ij}}\). Define \(m \star n\) by

\[(m \star n)_{ij} = \max_k (m_{ik} + n_{kj}), \]

This gives us an approximation \((M \cdot N)_{ij}\approx 2^{(m \star n)_{ij}}\)

Has anyone here encountered this before? It's essentially floating point matrix multiplication without the mantissa bits, but I'm wondering if there are any papers or resources dealing with it.

Given \(M, N\), matrices, let

\[m_{ij} = \lfloor \log_2 M_{ij} \rfloor \]

and similarly for \(n\). Then \(M_{ij} \approx 2^{m_{ij}}\). Define \(m \star n\) by

\[(m \star n)_{ij} = \max_k (m_{ik} + n_{kj}), \]

This gives us an approximation \((M \cdot N)_{ij}\approx 2^{(m \star n)_{ij}}\)

Has anyone here encountered this before? It's essentially floating point matrix multiplication without the mantissa bits, but I'm wondering if there are any papers or resources dealing with it.

The #gameoftrees FAQ summarizes our responses to several questions the internet was asking when the project first became known to the general public: https://gameoftrees.org/faq.html

I friggin' love this educational video.

It's a #Soviet-era #Russian film explaining #SpecialRelativity. I listen to it over and over to practice my Russian. Repetition and a familiar subject help a lot.

https://www.youtube.com/watch?v=IsuwQsDYJrk

Also, it's out of copyright. Soviet films belong to the people, comrade.

#Ghidra might be one of the coolest things I've played with lately, kind of bizarre seeing it running on #OpenBSD. The decompiler tool is.. something else. Also, notice RETGUARD prologue/epilogue?

On -current:

$ pkg_add ghidra

$ ghidraRun

Running NSA reverse engineering tool on the Huawei matebook, of course. 😏

Looking for undeadly.org staff contact :)

I digged up 13 #OpenBSD developer interviews in manageable format that we did for the 20th project anniversary.

It would be great if undeadly.org was willing to re-publish them (currently there is only https://undeadly.org/cgi?action=article&sid=20151030205937 pointing at dead links)

Minimal solution:

🍎=154476802108746166441951315019919837485664325669565431700026634898253202035277999,

🍍=36875131794129999827197811565225474825492979968971970996283137471637224634055579,

🍌=4373612677928697257861252602371390152816537558161613618621437993378423467772036

Powers of Two in Lexicographic Order

https://www.solipsys.co.uk/new/PowersOfTwoInLexOrder.html?sg28hn

(submitted by ColinWright)

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Theoretical Physics/Mathematics background; Finished university and currently up to nothing in particular. OpenBSD, Void and Alpine Linux user.

Barba Non Facit Mathematicum

Joined Jun 2017