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Christian Lawson-Perfect

I love Wikipedia's math gifs!
Here, an illustration of Bresenham's algorithm (

*Alan Partridge voice*
A haar!

(That's a photo of the sea, by the way)

@christianp That's what I love about listening to mathematicians. The conversation becomes quite dizzyingly elliptical, and yet communication is obviously taking place!

MetaFilter is giving server errors! What will I do with myself instead?

I had an *extremely mathematician* conversation with a Professor colleague yesterday.

Her: There's this puzzle where someone's getting on a train -
Me: And the answer is 1/2?
Her: Yes! It's obviously 1/2, but the hard part is to show why.
Me: Proof by induction.
Her: That's what I tried, too!
Everyone else at the table: 🤷‍♂️ 🤷

One of my favorite math teasers. Find theta in under a minute using only paper, pencil, and straight edge.

79. THE LOCKERS PUZZLE. A man had in his office three cupboards, each containing nine lockers,
as shown in the diagram. He told his clerk to place a different one-figure number on each locker of cupboard A, and to do the same in the case of B, and of C. As we are here allowed to call nought a digit,
and he was not prohibited from using nought as a number, he clearly had the option of omitting any one of ten digits from each cupboard.

It's just occurred to me that command-line installation instructions for software that runs on lots of OSes should be delivered as a Twine story: you can go down different paths depending on your particular setup.

(currently reading a set of 'instructions' that concatenates notes for a plethora of OSes and optional dependencies into one incomprehensible monologue)

🎈 🎉 🎈 🎉🎈 🎉 🎈
Mathmo party!
:descartes: :duchatelet: :euler: :lovelace: :leibniz:
👏 👏 👏 👏 🙌 🙌 🙌 🙌 has over 1000 registered users! Cor!

I'm thinking about tournament 'brackets', a month too late for Americans I think?

If you can predict the winner of a match 99.5% of the time, you've got a 50% chance of correctly predicting the outcome of all 127 matches in Wimbledon's ladies' singles tournament.

\(p = 0.99456\) is the solution to

\[ p^{2^7-1} = \frac{1}{2} \]

Log in with no password... #WebAuthN is a new standard from @W3C, already implemented in @Firefox, with @GoogleChrome and to follow 👏

the BBC's obsessive scare-quoting finally necessary

They did basically nothing for me! It was like film colour vs TV colour - a bit higher contrast, but it felt even harder to distinguish similar colours. They were the Enchroma glasses, and I'm a protanope.