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What should I change A to so that the number at the top is an integer?

Or what should I change B to? Or C?

@arjen alright, smart Alec!

@christianp oops always those zeroes!

So A can be any multiple of 9/4. I guess you wanted integer values? Then the smallest A that is int would be 36. Any multiple is also correct.

C has to be 8 if you want to modify it.

And, no natural number satifies the graph if you only want to modify B.

But, 3B / (B+5) has to be int; that does solve for B=-2, B=-4, B=-6, B=-8, and B=-10. There might be more, I do not have a good strategy to enumerate solutions though (but B=-12 is not a solution!).

@arjen are you sure about that? How about A=9, B=10, or C=2 (separately)?

@christianp BTW what problem motivated this puzzle?

@christianp How about A = 9, B = 0 and C=0?

@esclear any others?

@christianp A = 0 is certainly another possibility 🙃

@christianp A to 9 or C to 2, not got one for B yet...

@christianp I think I'd go with changing B to 10.

Arjen P. de Vries@arjen@idf.social@christianp changing the labels won't change anything ;-)