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PgSuper @PgSuper@mathstodon.xyz

Pinned toot

I like π pie, although I'm not sure about \( \pi^\pi \) pie

The despaquito

That's the only random thing I think of right now when reading about the pun

I wonder if some crazy mathematician ever thought of talking to a number as if it was a friend... (Because numbers are friends?)

"If life gives you lemons, that's really cool"
– Someone on Earth

philosophical thought Show more

Warning: Knowledges Show more

The story of Fermat's Last Theorem is truly fascinating... Was just reading about it and I'm truly stunned

In the same logic, I just found that for two consecutive numbers \( x \) and \( y \), where \( y = x - 1 \), the sum of their squares is equal to \(x^2 + y^2 = x \times 2y + 1\)

E.g.: \( 31^2 + 30^2 = 31 \times \left( 2\times 30 \right) + 1 = 1861\)

(Yes I know you can just substitute for \( y = x - 1 \), but again I was just randomly thinking of this)

PgSuper boosted

I can't seem to find the original photographer, but kudos for the timing

#Photography

and yes I know \( x^2 - y^2 = (x+y)(x-y) \), but I just wanted to share what I randomly thought of between my philosophical thoughts

So, I just found some interesting property of squared numbers by myself (which probably has been found already, but i just thought of it) which is that you can know the difference between two squares of consecutive numbers without knowing their values

E.g. I want to know \( 41^2 - 40^2 \). I don't know what their values are, but I can use this formula I just thought of: \( 2x - 1 \) (\( x \) is the higher number) so \( 2 * 41 - 1 = 81\) so \( 41^2 - 40^2 = 81 \)

really cool stuff

Let addition be an operation such that \( a + b = 1000 \). Therefore, \( 1 + 1 = 1000 \)

How to solve math *not* like a pro:

\[
\begin{split}
\frac{1}{n}\sin x =\\
\mathrm{(cancel\ n\ with\ n)}\operatorname{six} =\\
6
\end{split}
\]

I like π pie, although I'm not sure about \( \pi^\pi \) pie