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The current state of my #BigGAN dog evolution. (Reminder: the goal is to find the z vector generates an image most similar to the dog at the start of this thread)

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The neat thing about writing an internal memo instead of a real paper or report is that you can leave out all of the boilerplate like motivations.

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@Breakfastisready do you know what it translates to?

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@Limitcycle I never thought it would be possible for a mathematics meme to get so popular...

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I have to stop doing this thing where I start reading an article, and do a breadth-first traversal of all the related articles it links to. I may get a better picture than just reading the single article, but god damnit.

This one is also good

This has been proved 1000% by Tom Cruise himself.

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This is so cool, the absorb feature has finally landed:

gregoryszorc.com/blog/2018/11/

What it does: looks at your changes in your working directory and correctly absorbs them into the ancestor commits that touched the same files as your changes.

Great way to edit a stack of commits without having to manually sprinkle your changes across each individual commit!

This isn't , but here's a hashtag so that git users may stumble upon this feature.

Found these :chalkdust_scorpion:Journal collections in my University library today. Is anyone here into functional programming in Lisp or Haskell for example?

I have found these languages to be so much for beautiful than imperative languages thanks to their closer connection with mathematics.

@axiom you would probably be right. The formula (and thus the program) is given by defining a function Fib(n) that returns $(phi^n) - (-phi)^(-n))/sqrt(5)\ where phi = the Golden ratio, and the returned number is the nth Fib number @axiom the drawback however is that the formula uses the Golden ratio, which is infinitely long, so after some n the program fails in returning the correct nth Fib number due to the computers finite precision @axiom it is O(1) as the size of n is independent of the time it takes for the program to return the nth Fibonacci number. If n=1 or n=10,000, it will return the answer in the same amount of time. @axiom not algorithm, formula. SG boosted Google in a nutshell I love it when elegant mathematical formulas help you solve programming problems seamlessly. Nth Fib number in constant time? Yes please! SG boosted Throw these in a parallax scroller and you have some levels for a "planet of the ice giants" jump-and-run. #NeuralGlitch SG boosted Got my pumpkin for halloween Show more A Mastodon instance for maths people. The kind of people who make \(\pi z^2 \times a$ jokes.

Use $ and $ for inline LaTeX, and $ and $ for display mode.